Direct variation is a variation equation , relating one variable to one or more others using multiplication and or division.
We can use this to solve for d in a distance rate time problem. d=rt
if the rate is going to be a constant when the other variables are changing, then :
distance varies directly as time and
the distance is directly proportional to time.
Examples: page 321 in text has lots more
In electronics, Resistance of wire varies directly as its length R=kL
In medicine, dosage is directly proportionate to weight of person d=kw
Joint Variation is when one quantity may vary directly as a product of two or more other quantities.
If a variable y varies jointly with variable x and z, then y=kxz where k is the constant of proportionality.
In geometry the area A of a triangle varies jointly as its base b and height h. A=kbh
If F varies jointly as H and G then F=kHG
Z varies jointly as W and Y . If Z=330 when W=11 and Y=10, find Z when W=60 and Y=10
First find the variation: The variation is Z=kWY.
Second find k using the first set of values 330=k(11)(10) | 330=k(110) | k=330/110 | k=3
Third solve for Z using the second set of values and the k you just found… Z=(3)(60)(10) | z=1800
Inverse variation is when one quantity increases as the other decreases and vice versa. y=k/x
We would use this in a distance rate time equation (d=r/t | t=d/r) when we were solving for t
T=k/r
For the weight of an astronaut problem, the weight W of an object varies inversely as the square of the distance d from the center of the earth.When w=111, d=3978 find k. It really helped me to leave the numbers unmultiplied
W=k/d^2
111=k/3978^2 | k=111(3978^2)
now find w when d=434+3978
w=111(3978^2)/(434+3978)^2
w=90.24
Combined variation is awesome..
T varies direclty as the square of D and inversly as F. The variation is : (T=kD^2)/F
The number of phone calls between two cities, N, varies directly as the populations (p1+p2) and inversly as distance between, d
The variation is N=kp1p2/d
If 69000 is N number of calls and d distance between cities is 340 and p1 p2=(40800)(230000) then find k
69000= k((40800)(230000))/340
69,000=27,600,000k
k=69000/27600000
k=.0025
how many calls, N, are made when d=455and p1p2=(70,000)(160,000) and k=.0025
N=kp1p2/d
N=.0025(70,000)(160,000)/455
N=612538 rounded to nearest integer
F=kq1q2/d^2
F=6 when q1=9 and q2=3 and d=3
6=k(9)(3)/3^2
3k=6
k=2
find f when q1=6 q2=4 and d=2
F=(2)(6)(4)/2^2
f=12